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Solution - Absolute value equations

Exact form: x=7
x=7

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+5|+|x19|=0

Add |x19| to both sides of the equation:

|x+5|+|x19||x19|=|x19|

Simplify the arithmetic

|x+5|=|x19|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=|x19|
without the absolute value bars:

|x|=|y||x+5|=|x19|
x=+y(x+5)=(x19)
x=y(x+5)=(x19)
+x=y(x+5)=(x19)
x=y(x+5)=(x19)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=|x19|
x=+y , +x=y(x+5)=(x19)
x=y , x=y(x+5)=(x19)

3. Solve the two equations for x

12 additional steps

(x+5)=-(x-19)

Expand the parentheses:

(x+5)=-x+19

Add to both sides:

(x+5)+x=(-x+19)+x

Group like terms:

(x+x)+5=(-x+19)+x

Simplify the arithmetic:

2x+5=(-x+19)+x

Group like terms:

2x+5=(-x+x)+19

Simplify the arithmetic:

2x+5=19

Subtract from both sides:

(2x+5)-5=19-5

Simplify the arithmetic:

2x=195

Simplify the arithmetic:

2x=14

Divide both sides by :

(2x)2=142

Simplify the fraction:

x=142

Find the greatest common factor of the numerator and denominator:

x=(7·2)(1·2)

Factor out and cancel the greatest common factor:

x=7

6 additional steps

(x+5)=-(-(x-19))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x+5)=x-19

Subtract from both sides:

(x+5)-x=(x-19)-x

Group like terms:

(x-x)+5=(x-19)-x

Simplify the arithmetic:

5=(x-19)-x

Group like terms:

5=(x-x)-19

Simplify the arithmetic:

5=19

The statement is false:

5=19

The equation is false so it has no solution.

4. List the solutions

x=7
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=|x19|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.