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Solution - Absolute value equations

Exact form: x=113,1
x=\frac{11}{3} , 1
Mixed number form: x=323,1
x=3\frac{2}{3} , 1
Decimal form: x=3.667,1
x=3.667 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+3|=4|x2|
without the absolute value bars:

|x|=|y||x+3|=4|x2|
x=+y(x+3)=4(x2)
x=y(x+3)=4((x2))
+x=y(x+3)=4(x2)
x=y(x+3)=4(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+3|=4|x2|
x=+y , +x=y(x+3)=4(x2)
x=y , x=y(x+3)=4((x2))

2. Solve the two equations for x

13 additional steps

(x+3)=4·(x-2)

Expand the parentheses:

(x+3)=4x+4·-2

Simplify the arithmetic:

(x+3)=4x-8

Subtract from both sides:

(x+3)-4x=(4x-8)-4x

Group like terms:

(x-4x)+3=(4x-8)-4x

Simplify the arithmetic:

-3x+3=(4x-8)-4x

Group like terms:

-3x+3=(4x-4x)-8

Simplify the arithmetic:

3x+3=8

Subtract from both sides:

(-3x+3)-3=-8-3

Simplify the arithmetic:

3x=83

Simplify the arithmetic:

3x=11

Divide both sides by :

(-3x)-3=-11-3

Cancel out the negatives:

3x3=-11-3

Simplify the fraction:

x=-11-3

Cancel out the negatives:

x=113

15 additional steps

(x+3)=4·(-(x-2))

Expand the parentheses:

(x+3)=4·(-x+2)

(x+3)=4·-x+4·2

Group like terms:

(x+3)=(4·-1)x+4·2

Multiply the coefficients:

(x+3)=-4x+4·2

Simplify the arithmetic:

(x+3)=-4x+8

Add to both sides:

(x+3)+4x=(-4x+8)+4x

Group like terms:

(x+4x)+3=(-4x+8)+4x

Simplify the arithmetic:

5x+3=(-4x+8)+4x

Group like terms:

5x+3=(-4x+4x)+8

Simplify the arithmetic:

5x+3=8

Subtract from both sides:

(5x+3)-3=8-3

Simplify the arithmetic:

5x=83

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=55

Simplify the fraction:

x=55

Simplify the fraction:

x=1

3. List the solutions

x=113,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+3|
y=4|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.