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Solution - Absolute value equations

Exact form:

x = \frac{6}{11}, 0

x=\frac{6}{11} , 0

Decimal form:

x = 0.545, 0

x=0.545 , 0

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| x + 3 | = 3 | 4 x - 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| x + 3 \| = 3 \| 4 x - 1 \|$
$x = + y$	$(x + 3) = 3 (4 x - 1)$
$x = - y$	$(x + 3) = 3 (- (4 x - 1))$
$+ x = y$	$(x + 3) = 3 (4 x - 1)$
$- x = y$	$- (x + 3) = 3 (4 x - 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| x + 3 \| = 3 \| 4 x - 1 \|$
$x = + y$ , $+ x = y$	$(x + 3) = 3 (4 x - 1)$
$x = - y$ , $- x = y$	$(x + 3) = 3 (- (4 x - 1))$

2. Solve the two equations for x

14 additional steps

$(x + 3) = 3 \cdot (4 x - 1)$

Expand the parentheses:

$(x + 3) = 3 \cdot 4 x + 3 \cdot - 1$

Multiply the coefficients:

$(x + 3) = 12 x + 3 \cdot - 1$

Simplify the arithmetic:

$(x + 3) = 12 x - 3$

Subtract from both sides:

$(x + 3) - 12 x = (12 x - 3) - 12 x$

Group like terms:

$(x - 12 x) + 3 = (12 x - 3) - 12 x$

Simplify the arithmetic:

$- 11 x + 3 = (12 x - 3) - 12 x$

Group like terms:

$- 11 x + 3 = (12 x - 12 x) - 3$

Simplify the arithmetic:

$- 11 x + 3 = - 3$

Subtract from both sides:

$(- 11 x + 3) - 3 = - 3 - 3$

Simplify the arithmetic:

$- 11 x = - 3 - 3$

Simplify the arithmetic:

$- 11 x = - 6$

Divide both sides by :

$\frac{(- 11 x)}{- 11} = \frac{- 6}{- 11}$

Cancel out the negatives:

$\frac{11 x}{11} = \frac{- 6}{- 11}$

Simplify the fraction:

$x = \frac{- 6}{- 11}$

Cancel out the negatives:

$x = \frac{6}{11}$

12 additional steps

$(x + 3) = 3 \cdot (- (4 x - 1))$

Expand the parentheses:

$(x + 3) = 3 \cdot (- 4 x + 1)$

Expand the parentheses:

$(x + 3) = 3 \cdot - 4 x + 3 \cdot 1$

Multiply the coefficients:

$(x + 3) = - 12 x + 3 \cdot 1$

Simplify the arithmetic:

$(x + 3) = - 12 x + 3$

Add to both sides:

$(x + 3) + 12 x = (- 12 x + 3) + 12 x$

Group like terms:

$(x + 12 x) + 3 = (- 12 x + 3) + 12 x$

Simplify the arithmetic:

$13 x + 3 = (- 12 x + 3) + 12 x$

Group like terms:

$13 x + 3 = (- 12 x + 12 x) + 3$

Simplify the arithmetic:

$13 x + 3 = 3$

Subtract from both sides:

$(13 x + 3) - 3 = 3 - 3$

Simplify the arithmetic:

$13 x = 3 - 3$

Simplify the arithmetic:

$13 x = 0$

Divide both sides by the coefficient:

$x = 0$

3. List the solutions

$x = \frac{6}{11}, 0$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | x + 3 |$
$y = 3 | 4 x - 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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