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Solution - Absolute value equations

Exact form: x=53,15
x=\frac{5}{3} , \frac{1}{5}
Mixed number form: x=123,15
x=1\frac{2}{3} , \frac{1}{5}
Decimal form: x=1.667,0.2
x=1.667 , 0.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+2||4x3|=0

Add |4x3| to both sides of the equation:

|x+2||4x3|+|4x3|=|4x3|

Simplify the arithmetic

|x+2|=|4x3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+2|=|4x3|
without the absolute value bars:

|x|=|y||x+2|=|4x3|
x=+y(x+2)=(4x3)
x=y(x+2)=((4x3))
+x=y(x+2)=(4x3)
x=y(x+2)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+2|=|4x3|
x=+y , +x=y(x+2)=(4x3)
x=y , x=y(x+2)=((4x3))

3. Solve the two equations for x

11 additional steps

(x+2)=(4x-3)

Subtract from both sides:

(x+2)-4x=(4x-3)-4x

Group like terms:

(x-4x)+2=(4x-3)-4x

Simplify the arithmetic:

-3x+2=(4x-3)-4x

Group like terms:

-3x+2=(4x-4x)-3

Simplify the arithmetic:

3x+2=3

Subtract from both sides:

(-3x+2)-2=-3-2

Simplify the arithmetic:

3x=32

Simplify the arithmetic:

3x=5

Divide both sides by :

(-3x)-3=-5-3

Cancel out the negatives:

3x3=-5-3

Simplify the fraction:

x=-5-3

Cancel out the negatives:

x=53

10 additional steps

(x+2)=-(4x-3)

Expand the parentheses:

(x+2)=-4x+3

Add to both sides:

(x+2)+4x=(-4x+3)+4x

Group like terms:

(x+4x)+2=(-4x+3)+4x

Simplify the arithmetic:

5x+2=(-4x+3)+4x

Group like terms:

5x+2=(-4x+4x)+3

Simplify the arithmetic:

5x+2=3

Subtract from both sides:

(5x+2)-2=3-2

Simplify the arithmetic:

5x=32

Simplify the arithmetic:

5x=1

Divide both sides by :

(5x)5=15

Simplify the fraction:

x=15

4. List the solutions

x=53,15
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x+2|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.