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Solution - Absolute value equations

Exact form: x=4,0
x=4 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+2|=2|x1|
without the absolute value bars:

|x|=|y||x+2|=2|x1|
x=+y(x+2)=2(x1)
x=y(x+2)=2((x1))
+x=y(x+2)=2(x1)
x=y(x+2)=2(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+2|=2|x1|
x=+y , +x=y(x+2)=2(x1)
x=y , x=y(x+2)=2((x1))

2. Solve the two equations for x

12 additional steps

(x+2)=2·(x-1)

Expand the parentheses:

(x+2)=2x+2·-1

Simplify the arithmetic:

(x+2)=2x-2

Subtract from both sides:

(x+2)-2x=(2x-2)-2x

Group like terms:

(x-2x)+2=(2x-2)-2x

Simplify the arithmetic:

-x+2=(2x-2)-2x

Group like terms:

-x+2=(2x-2x)-2

Simplify the arithmetic:

x+2=2

Subtract from both sides:

(-x+2)-2=-2-2

Simplify the arithmetic:

x=22

Simplify the arithmetic:

x=4

Multiply both sides by :

-x·-1=-4·-1

Remove the one(s):

x=-4·-1

Simplify the arithmetic:

x=4

13 additional steps

(x+2)=2·(-(x-1))

Expand the parentheses:

(x+2)=2·(-x+1)

(x+2)=2·-x+2·1

Group like terms:

(x+2)=(2·-1)x+2·1

Multiply the coefficients:

(x+2)=-2x+2·1

Simplify the arithmetic:

(x+2)=-2x+2

Add to both sides:

(x+2)+2x=(-2x+2)+2x

Group like terms:

(x+2x)+2=(-2x+2)+2x

Simplify the arithmetic:

3x+2=(-2x+2)+2x

Group like terms:

3x+2=(-2x+2x)+2

Simplify the arithmetic:

3x+2=2

Subtract from both sides:

(3x+2)-2=2-2

Simplify the arithmetic:

3x=22

Simplify the arithmetic:

3x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=4,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+2|
y=2|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.