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Solution - Absolute value equations

Exact form: x=5,-52
x=5 , -\frac{5}{2}
Mixed number form: x=5,-212
x=5 , -2\frac{1}{2}
Decimal form: x=5,2.5
x=5 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+10|=|3x|
without the absolute value bars:

|x|=|y||x+10|=|3x|
x=+y(x+10)=(3x)
x=y(x+10)=(3x)
+x=y(x+10)=(3x)
x=y(x+10)=(3x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+10|=|3x|
x=+y , +x=y(x+10)=(3x)
x=y , x=y(x+10)=(3x)

2. Solve the two equations for x

12 additional steps

(x+10)=3x

Subtract from both sides:

(x+10)-3x=(3x)-3x

Group like terms:

(x-3x)+10=(3x)-3x

Simplify the arithmetic:

-2x+10=(3x)-3x

Simplify the arithmetic:

2x+10=0

Subtract from both sides:

(-2x+10)-10=0-10

Simplify the arithmetic:

2x=010

Simplify the arithmetic:

2x=10

Divide both sides by :

(-2x)-2=-10-2

Cancel out the negatives:

2x2=-10-2

Simplify the fraction:

x=-10-2

Cancel out the negatives:

x=102

Find the greatest common factor of the numerator and denominator:

x=(5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

9 additional steps

(x+10)=-3x

Subtract from both sides:

(x+10)-10=(-3x)-10

Simplify the arithmetic:

x=(-3x)-10

Add to both sides:

x+3x=((-3x)-10)+3x

Simplify the arithmetic:

4x=((-3x)-10)+3x

Group like terms:

4x=(-3x+3x)-10

Simplify the arithmetic:

4x=10

Divide both sides by :

(4x)4=-104

Simplify the fraction:

x=-104

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(2·2)

Factor out and cancel the greatest common factor:

x=-52

3. List the solutions

x=5,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+10|
y=|3x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.