Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=53,35
x=\frac{5}{3} , \frac{3}{5}
Mixed number form: x=123,35
x=1\frac{2}{3} , \frac{3}{5}
Decimal form: x=1.667,0.6
x=1.667 , 0.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=4|x1|
without the absolute value bars:

|x|=|y||x+1|=4|x1|
x=+y(x+1)=4(x1)
x=y(x+1)=4((x1))
+x=y(x+1)=4(x1)
x=y(x+1)=4(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=4|x1|
x=+y , +x=y(x+1)=4(x1)
x=y , x=y(x+1)=4((x1))

2. Solve the two equations for x

13 additional steps

(x+1)=4·(x-1)

Expand the parentheses:

(x+1)=4x+4·-1

Simplify the arithmetic:

(x+1)=4x-4

Subtract from both sides:

(x+1)-4x=(4x-4)-4x

Group like terms:

(x-4x)+1=(4x-4)-4x

Simplify the arithmetic:

-3x+1=(4x-4)-4x

Group like terms:

-3x+1=(4x-4x)-4

Simplify the arithmetic:

3x+1=4

Subtract from both sides:

(-3x+1)-1=-4-1

Simplify the arithmetic:

3x=41

Simplify the arithmetic:

3x=5

Divide both sides by :

(-3x)-3=-5-3

Cancel out the negatives:

3x3=-5-3

Simplify the fraction:

x=-5-3

Cancel out the negatives:

x=53

14 additional steps

(x+1)=4·(-(x-1))

Expand the parentheses:

(x+1)=4·(-x+1)

(x+1)=4·-x+4·1

Group like terms:

(x+1)=(4·-1)x+4·1

Multiply the coefficients:

(x+1)=-4x+4·1

Simplify the arithmetic:

(x+1)=-4x+4

Add to both sides:

(x+1)+4x=(-4x+4)+4x

Group like terms:

(x+4x)+1=(-4x+4)+4x

Simplify the arithmetic:

5x+1=(-4x+4)+4x

Group like terms:

5x+1=(-4x+4x)+4

Simplify the arithmetic:

5x+1=4

Subtract from both sides:

(5x+1)-1=4-1

Simplify the arithmetic:

5x=41

Simplify the arithmetic:

5x=3

Divide both sides by :

(5x)5=35

Simplify the fraction:

x=35

3. List the solutions

x=53,35
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=4|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.