Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=5
x=-5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=|x9|
without the absolute value bars:

|x|=|y||x+1|=|x9|
x=+y(x+1)=(x9)
x=y(x+1)=(x9)
+x=y(x+1)=(x9)
x=y(x+1)=(x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=|x9|
x=+y , +x=y(x+1)=(x9)
x=y , x=y(x+1)=(x9)

2. Solve the two equations for x

11 additional steps

(x+1)=(-x-9)

Add to both sides:

(x+1)+x=(-x-9)+x

Group like terms:

(x+x)+1=(-x-9)+x

Simplify the arithmetic:

2x+1=(-x-9)+x

Group like terms:

2x+1=(-x+x)-9

Simplify the arithmetic:

2x+1=9

Subtract from both sides:

(2x+1)-1=-9-1

Simplify the arithmetic:

2x=91

Simplify the arithmetic:

2x=10

Divide both sides by :

(2x)2=-102

Simplify the fraction:

x=-102

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

6 additional steps

(x+1)=-(-x-9)

Expand the parentheses:

(x+1)=x+9

Subtract from both sides:

(x+1)-x=(x+9)-x

Group like terms:

(x-x)+1=(x+9)-x

Simplify the arithmetic:

1=(x+9)-x

Group like terms:

1=(x-x)+9

Simplify the arithmetic:

1=9

The statement is false:

1=9

The equation is false so it has no solution.

3. List the solutions

x=5
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=|x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.