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Solution - Absolute value equations

Exact form:

x = - \frac{13}{5}, - \frac{11}{3}

x=-\frac{13}{5} , -\frac{11}{3}

Mixed number form:

x = - 2 \frac{3}{5}, - 3 \frac{2}{3}

x=-2\frac{3}{5} , -3\frac{2}{3}

Decimal form:

x = - 2.6, - 3.667

x=-2.6 , -3.667

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| x + 1 | + 4 | x + 3 | = 0$

Add $- 4 | x + 3 |$ to both sides of the equation:

$| x + 1 | + 4 | x + 3 | - 4 | x + 3 | = - 4 | x + 3 |$

Simplify the arithmetic

$| x + 1 | = - 4 | x + 3 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| x + 1 | = - 4 | x + 3 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| x + 1 \| = - 4 \| x + 3 \|$
$x = + y$	$(x + 1) = - 4 (x + 3)$
$x = - y$	$(x + 1) = - 4 (- (x + 3))$
$+ x = y$	$(x + 1) = - 4 (x + 3)$
$- x = y$	$- (x + 1) = - 4 (x + 3)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| x + 1 \| = - 4 \| x + 3 \|$
$x = + y$ , $+ x = y$	$(x + 1) = - 4 (x + 3)$
$x = - y$ , $- x = y$	$(x + 1) = - 4 (- (x + 3))$

3. Solve the two equations for x

11 additional steps

$(x + 1) = - 4 \cdot (x + 3)$

Expand the parentheses:

$(x + 1) = - 4 x - 4 \cdot 3$

Simplify the arithmetic:

$(x + 1) = - 4 x - 12$

Add to both sides:

$(x + 1) + 4 x = (- 4 x - 12) + 4 x$

Group like terms:

$(x + 4 x) + 1 = (- 4 x - 12) + 4 x$

Simplify the arithmetic:

$5 x + 1 = (- 4 x - 12) + 4 x$

Group like terms:

$5 x + 1 = (- 4 x + 4 x) - 12$

Simplify the arithmetic:

$5 x + 1 = - 12$

Subtract from both sides:

$(5 x + 1) - 1 = - 12 - 1$

Simplify the arithmetic:

$5 x = - 12 - 1$

Simplify the arithmetic:

$5 x = - 13$

Divide both sides by :

$\frac{(5 x)}{5} = \frac{- 13}{5}$

Simplify the fraction:

$x = \frac{- 13}{5}$

16 additional steps

$(x + 1) = - 4 \cdot (- (x + 3))$

Expand the parentheses:

$(x + 1) = - 4 \cdot (- x - 3)$

$(x + 1) = - 4 \cdot - x - 4 \cdot - 3$

Group like terms:

$(x + 1) = (- 4 \cdot - 1) x - 4 \cdot - 3$

Multiply the coefficients:

$(x + 1) = 4 x - 4 \cdot - 3$

Simplify the arithmetic:

$(x + 1) = 4 x + 12$

Subtract from both sides:

$(x + 1) - 4 x = (4 x + 12) - 4 x$

Group like terms:

$(x - 4 x) + 1 = (4 x + 12) - 4 x$

Simplify the arithmetic:

$- 3 x + 1 = (4 x + 12) - 4 x$

Group like terms:

$- 3 x + 1 = (4 x - 4 x) + 12$

Simplify the arithmetic:

$- 3 x + 1 = 12$

Subtract from both sides:

$(- 3 x + 1) - 1 = 12 - 1$

Simplify the arithmetic:

$- 3 x = 12 - 1$

Simplify the arithmetic:

$- 3 x = 11$

Divide both sides by :

$\frac{(- 3 x)}{- 3} = \frac{11}{- 3}$

Cancel out the negatives:

$\frac{3 x}{3} = \frac{11}{- 3}$

Simplify the fraction:

$x = \frac{11}{- 3}$

Move the negative sign from the denominator to the numerator:

$x = \frac{- 11}{3}$

4. List the solutions

$x = - \frac{13}{5}, - \frac{11}{3}$
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
$y = | x + 1 |$
$y = - 4 | x + 3 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved