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Solution - Absolute value equations

Exact form: x=-32
x=-\frac{3}{2}
Mixed number form: x=-112
x=-1\frac{1}{2}
Decimal form: x=1.5
x=-1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+1|+|x+2|=0

Add |x+2| to both sides of the equation:

|x+1|+|x+2||x+2|=|x+2|

Simplify the arithmetic

|x+1|=|x+2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=|x+2|
without the absolute value bars:

|x|=|y||x+1|=|x+2|
x=+y(x+1)=(x+2)
x=y(x+1)=(x+2)
+x=y(x+1)=(x+2)
x=y(x+1)=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=|x+2|
x=+y , +x=y(x+1)=(x+2)
x=y , x=y(x+1)=(x+2)

3. Solve the two equations for x

10 additional steps

(x+1)=-(x+2)

Expand the parentheses:

(x+1)=-x-2

Add to both sides:

(x+1)+x=(-x-2)+x

Group like terms:

(x+x)+1=(-x-2)+x

Simplify the arithmetic:

2x+1=(-x-2)+x

Group like terms:

2x+1=(-x+x)-2

Simplify the arithmetic:

2x+1=2

Subtract from both sides:

(2x+1)-1=-2-1

Simplify the arithmetic:

2x=21

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=-32

Simplify the fraction:

x=-32

6 additional steps

(x+1)=-(-(x+2))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x+1)=x+2

Subtract from both sides:

(x+1)-x=(x+2)-x

Group like terms:

(x-x)+1=(x+2)-x

Simplify the arithmetic:

1=(x+2)-x

Group like terms:

1=(x-x)+2

Simplify the arithmetic:

1=2

The statement is false:

1=2

The equation is false so it has no solution.

4. List the solutions

x=-32
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.