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Solution - Absolute value equations

Exact form: x=43,6
x=\frac{4}{3} , 6
Mixed number form: x=113,6
x=1\frac{1}{3} , 6
Decimal form: x=1.333,6
x=1.333 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+1|+|2x5|=0

Add |2x5| to both sides of the equation:

|x+1|+|2x5||2x5|=|2x5|

Simplify the arithmetic

|x+1|=|2x5|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=|2x5|
without the absolute value bars:

|x|=|y||x+1|=|2x5|
x=+y(x+1)=(2x5)
x=y(x+1)=(2x5)
+x=y(x+1)=(2x5)
x=y(x+1)=(2x5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=|2x5|
x=+y , +x=y(x+1)=(2x5)
x=y , x=y(x+1)=(2x5)

3. Solve the two equations for x

10 additional steps

(x+1)=-(2x-5)

Expand the parentheses:

(x+1)=-2x+5

Add to both sides:

(x+1)+2x=(-2x+5)+2x

Group like terms:

(x+2x)+1=(-2x+5)+2x

Simplify the arithmetic:

3x+1=(-2x+5)+2x

Group like terms:

3x+1=(-2x+2x)+5

Simplify the arithmetic:

3x+1=5

Subtract from both sides:

(3x+1)-1=5-1

Simplify the arithmetic:

3x=51

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=43

Simplify the fraction:

x=43

11 additional steps

(x+1)=-(-(2x-5))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x+1)=2x-5

Subtract from both sides:

(x+1)-2x=(2x-5)-2x

Group like terms:

(x-2x)+1=(2x-5)-2x

Simplify the arithmetic:

-x+1=(2x-5)-2x

Group like terms:

-x+1=(2x-2x)-5

Simplify the arithmetic:

x+1=5

Subtract from both sides:

(-x+1)-1=-5-1

Simplify the arithmetic:

x=51

Simplify the arithmetic:

x=6

Multiply both sides by :

-x·-1=-6·-1

Remove the one(s):

x=-6·-1

Simplify the arithmetic:

x=6

4. List the solutions

x=43,6
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=|2x5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.