Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: t=-12,14
t=-\frac{1}{2} , \frac{1}{4}
Decimal form: t=0.5,0.25
t=-0.5 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|t1|3|t|=0

Add 3|t| to both sides of the equation:

|t1|3|t|+3|t|=3|t|

Simplify the arithmetic

|t1|=3|t|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|t1|=3|t|
without the absolute value bars:

|x|=|y||t1|=3|t|
x=+y(t1)=3(t)
x=y(t1)=3((t))
+x=y(t1)=3(t)
x=y(t1)=3(t)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||t1|=3|t|
x=+y , +x=y(t1)=3(t)
x=y , x=y(t1)=3((t))

3. Solve the two equations for t

10 additional steps

(t-1)=3t

Subtract from both sides:

(t-1)-3t=(3t)-3t

Group like terms:

(t-3t)-1=(3t)-3t

Simplify the arithmetic:

-2t-1=(3t)-3t

Simplify the arithmetic:

2t1=0

Add to both sides:

(-2t-1)+1=0+1

Simplify the arithmetic:

2t=0+1

Simplify the arithmetic:

2t=1

Divide both sides by :

(-2t)-2=1-2

Cancel out the negatives:

2t2=1-2

Simplify the fraction:

t=1-2

Move the negative sign from the denominator to the numerator:

t=-12

10 additional steps

(t-1)=3·-t

Group like terms:

(t-1)=(3·-1)t

Multiply the coefficients:

(t-1)=-3t

Add to both sides:

(t-1)+3t=(-3t)+3t

Group like terms:

(t+3t)-1=(-3t)+3t

Simplify the arithmetic:

4t-1=(-3t)+3t

Simplify the arithmetic:

4t1=0

Add to both sides:

(4t-1)+1=0+1

Simplify the arithmetic:

4t=0+1

Simplify the arithmetic:

4t=1

Divide both sides by :

(4t)4=14

Simplify the fraction:

t=14

4. List the solutions

t=-12,14
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|t1|
y=3|t|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.