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Solution - Absolute value equations

Exact form: r=8
r=-8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|r+4|=|r+12|
without the absolute value bars:

|x|=|y||r+4|=|r+12|
x=+y(r+4)=(r+12)
x=y(r+4)=(r+12)
+x=y(r+4)=(r+12)
x=y(r+4)=(r+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||r+4|=|r+12|
x=+y , +x=y(r+4)=(r+12)
x=y , x=y(r+4)=(r+12)

2. Solve the two equations for r

5 additional steps

(r+4)=(r+12)

Subtract from both sides:

(r+4)-r=(r+12)-r

Group like terms:

(r-r)+4=(r+12)-r

Simplify the arithmetic:

4=(r+12)-r

Group like terms:

4=(r-r)+12

Simplify the arithmetic:

4=12

The statement is false:

4=12

The equation is false so it has no solution.

12 additional steps

(r+4)=-(r+12)

Expand the parentheses:

(r+4)=-r-12

Add to both sides:

(r+4)+r=(-r-12)+r

Group like terms:

(r+r)+4=(-r-12)+r

Simplify the arithmetic:

2r+4=(-r-12)+r

Group like terms:

2r+4=(-r+r)-12

Simplify the arithmetic:

2r+4=12

Subtract from both sides:

(2r+4)-4=-12-4

Simplify the arithmetic:

2r=124

Simplify the arithmetic:

2r=16

Divide both sides by :

(2r)2=-162

Simplify the fraction:

r=-162

Find the greatest common factor of the numerator and denominator:

r=(-8·2)(1·2)

Factor out and cancel the greatest common factor:

r=8

3. Graph

Each line represents the function of one side of the equation:
y=|r+4|
y=|r+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.