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Solution - Absolute value equations

Exact form: n=14,6
n=-14 , -6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|n+2|=2|n+8|
without the absolute value bars:

|x|=|y||n+2|=2|n+8|
x=+y(n+2)=2(n+8)
x=y(n+2)=2((n+8))
+x=y(n+2)=2(n+8)
x=y(n+2)=2(n+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||n+2|=2|n+8|
x=+y , +x=y(n+2)=2(n+8)
x=y , x=y(n+2)=2((n+8))

2. Solve the two equations for n

12 additional steps

(n+2)=2·(n+8)

Expand the parentheses:

(n+2)=2n+2·8

Simplify the arithmetic:

(n+2)=2n+16

Subtract from both sides:

(n+2)-2n=(2n+16)-2n

Group like terms:

(n-2n)+2=(2n+16)-2n

Simplify the arithmetic:

-n+2=(2n+16)-2n

Group like terms:

-n+2=(2n-2n)+16

Simplify the arithmetic:

n+2=16

Subtract from both sides:

(-n+2)-2=16-2

Simplify the arithmetic:

n=162

Simplify the arithmetic:

n=14

Multiply both sides by :

-n·-1=14·-1

Remove the one(s):

n=14·-1

Simplify the arithmetic:

n=14

16 additional steps

(n+2)=2·(-(n+8))

Expand the parentheses:

(n+2)=2·(-n-8)

(n+2)=2·-n+2·-8

Group like terms:

(n+2)=(2·-1)n+2·-8

Multiply the coefficients:

(n+2)=-2n+2·-8

Simplify the arithmetic:

(n+2)=-2n-16

Add to both sides:

(n+2)+2n=(-2n-16)+2n

Group like terms:

(n+2n)+2=(-2n-16)+2n

Simplify the arithmetic:

3n+2=(-2n-16)+2n

Group like terms:

3n+2=(-2n+2n)-16

Simplify the arithmetic:

3n+2=16

Subtract from both sides:

(3n+2)-2=-16-2

Simplify the arithmetic:

3n=162

Simplify the arithmetic:

3n=18

Divide both sides by :

(3n)3=-183

Simplify the fraction:

n=-183

Find the greatest common factor of the numerator and denominator:

n=(-6·3)(1·3)

Factor out and cancel the greatest common factor:

n=6

3. List the solutions

n=14,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|n+2|
y=2|n+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.