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Solution - Absolute value equations

Exact form: m=0,92
m=0 , \frac{9}{2}
Mixed number form: m=0,412
m=0 , 4\frac{1}{2}
Decimal form: m=0,4.5
m=0 , 4.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|m9|=|3m9|
without the absolute value bars:

|x|=|y||m9|=|3m9|
x=+y(m9)=(3m9)
x=y(m9)=(3m9)
+x=y(m9)=(3m9)
x=y(m9)=(3m9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||m9|=|3m9|
x=+y , +x=y(m9)=(3m9)
x=y , x=y(m9)=(3m9)

2. Solve the two equations for m

8 additional steps

(m-9)=(3m-9)

Subtract from both sides:

(m-9)-3m=(3m-9)-3m

Group like terms:

(m-3m)-9=(3m-9)-3m

Simplify the arithmetic:

-2m-9=(3m-9)-3m

Group like terms:

-2m-9=(3m-3m)-9

Simplify the arithmetic:

-2m-9=-9

Add to both sides:

(-2m-9)+9=-9+9

Simplify the arithmetic:

-2m=-9+9

Simplify the arithmetic:

-2m=0

Divide both sides by the coefficient:

m=0

12 additional steps

(m-9)=-(3m-9)

Expand the parentheses:

(m-9)=-3m+9

Add to both sides:

(m-9)+3m=(-3m+9)+3m

Group like terms:

(m+3m)-9=(-3m+9)+3m

Simplify the arithmetic:

4m-9=(-3m+9)+3m

Group like terms:

4m-9=(-3m+3m)+9

Simplify the arithmetic:

4m-9=9

Add to both sides:

(4m-9)+9=9+9

Simplify the arithmetic:

4m=9+9

Simplify the arithmetic:

4m=18

Divide both sides by :

(4m)4=184

Simplify the fraction:

m=184

Find the greatest common factor of the numerator and denominator:

m=(9·2)(2·2)

Factor out and cancel the greatest common factor:

m=92

3. List the solutions

m=0,92
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|m9|
y=|3m9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.