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Solution - Absolute value equations

Exact form: d=1,9
d=1 , 9

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|d+3|=|2d+6|
without the absolute value bars:

|x|=|y||d+3|=|2d+6|
x=+y(d+3)=(2d+6)
x=y(d+3)=(2d+6)
+x=y(d+3)=(2d+6)
x=y(d+3)=(2d+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||d+3|=|2d+6|
x=+y , +x=y(d+3)=(2d+6)
x=y , x=y(d+3)=(2d+6)

2. Solve the two equations for d

10 additional steps

(d+3)=(-2d+6)

Add to both sides:

(d+3)+2d=(-2d+6)+2d

Group like terms:

(d+2d)+3=(-2d+6)+2d

Simplify the arithmetic:

3d+3=(-2d+6)+2d

Group like terms:

3d+3=(-2d+2d)+6

Simplify the arithmetic:

3d+3=6

Subtract from both sides:

(3d+3)-3=6-3

Simplify the arithmetic:

3d=63

Simplify the arithmetic:

3d=3

Divide both sides by :

(3d)3=33

Simplify the fraction:

d=33

Simplify the fraction:

d=1

11 additional steps

(d+3)=-(-2d+6)

Expand the parentheses:

(d+3)=2d-6

Subtract from both sides:

(d+3)-2d=(2d-6)-2d

Group like terms:

(d-2d)+3=(2d-6)-2d

Simplify the arithmetic:

-d+3=(2d-6)-2d

Group like terms:

-d+3=(2d-2d)-6

Simplify the arithmetic:

d+3=6

Subtract from both sides:

(-d+3)-3=-6-3

Simplify the arithmetic:

d=63

Simplify the arithmetic:

d=9

Multiply both sides by :

-d·-1=-9·-1

Remove the one(s):

d=-9·-1

Simplify the arithmetic:

d=9

3. List the solutions

d=1,9
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|d+3|
y=|2d+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.