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Solution - Absolute value equations

Exact form: b=4,1
b=4 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|b+6|=|3b2|
without the absolute value bars:

|x|=|y||b+6|=|3b2|
x=+y(b+6)=(3b2)
x=y(b+6)=(3b2)
+x=y(b+6)=(3b2)
x=y(b+6)=(3b2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||b+6|=|3b2|
x=+y , +x=y(b+6)=(3b2)
x=y , x=y(b+6)=(3b2)

2. Solve the two equations for b

13 additional steps

(b+6)=(3b-2)

Subtract from both sides:

(b+6)-3b=(3b-2)-3b

Group like terms:

(b-3b)+6=(3b-2)-3b

Simplify the arithmetic:

-2b+6=(3b-2)-3b

Group like terms:

-2b+6=(3b-3b)-2

Simplify the arithmetic:

-2b+6=-2

Subtract from both sides:

(-2b+6)-6=-2-6

Simplify the arithmetic:

-2b=-2-6

Simplify the arithmetic:

-2b=-8

Divide both sides by :

(-2b)-2=-8-2

Cancel out the negatives:

2b2=-8-2

Simplify the fraction:

b=-8-2

Cancel out the negatives:

b=82

Find the greatest common factor of the numerator and denominator:

b=(4·2)(1·2)

Factor out and cancel the greatest common factor:

b=4

11 additional steps

(b+6)=-(3b-2)

Expand the parentheses:

(b+6)=-3b+2

Add to both sides:

(b+6)+3b=(-3b+2)+3b

Group like terms:

(b+3b)+6=(-3b+2)+3b

Simplify the arithmetic:

4b+6=(-3b+2)+3b

Group like terms:

4b+6=(-3b+3b)+2

Simplify the arithmetic:

4b+6=2

Subtract from both sides:

(4b+6)-6=2-6

Simplify the arithmetic:

4b=2-6

Simplify the arithmetic:

4b=-4

Divide both sides by :

(4b)4=-44

Simplify the fraction:

b=-44

Simplify the fraction:

b=-1

3. List the solutions

b=4,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|b+6|
y=|3b2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.