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Solution - Absolute value equations

Exact form:

a = \frac{1}{2}

a=\frac{1}{2}

Decimal form:

a = 0.5

a=0.5

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| a - 3 | - | a + 2 | = 0$

Add $| a + 2 |$ to both sides of the equation:

$| a - 3 | - | a + 2 | + | a + 2 | = | a + 2 |$

Simplify the arithmetic

$| a - 3 | = | a + 2 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| a - 3 | = | a + 2 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| a - 3 \| = \| a + 2 \|$
$x = + y$	$(a - 3) = (a + 2)$
$x = - y$	$(a - 3) = (- (a + 2))$
$+ x = y$	$(a - 3) = (a + 2)$
$- x = y$	$- (a - 3) = (a + 2)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| a - 3 \| = \| a + 2 \|$
$x = + y$ , $+ x = y$	$(a - 3) = (a + 2)$
$x = - y$ , $- x = y$	$(a - 3) = (- (a + 2))$

3. Solve the two equations for a

5 additional steps

$(a - 3) = (a + 2)$

Subtract from both sides:

$(a - 3) - a = (a + 2) - a$

Group like terms:

$(a - a) - 3 = (a + 2) - a$

Simplify the arithmetic:

$- 3 = (a + 2) - a$

Group like terms:

$- 3 = (a - a) + 2$

Simplify the arithmetic:

$- 3 = 2$

The statement is false:

$- 3 = 2$

The equation is false so it has no solution.

10 additional steps

$(a - 3) = - (a + 2)$

Expand the parentheses:

$(a - 3) = - a - 2$

Add to both sides:

$(a - 3) + a = (- a - 2) + a$

Group like terms:

$(a + a) - 3 = (- a - 2) + a$

Simplify the arithmetic:

$2 a - 3 = (- a - 2) + a$

Group like terms:

$2 a - 3 = (- a + a) - 2$

Simplify the arithmetic:

$2 a - 3 = - 2$

Add to both sides:

$(2 a - 3) + 3 = - 2 + 3$

Simplify the arithmetic:

$2 a = - 2 + 3$

Simplify the arithmetic:

$2 a = 1$

Divide both sides by :

$\frac{(2 a)}{2} = \frac{1}{2}$

Simplify the fraction:

$a = \frac{1}{2}$

4. Graph

Each line represents the function of one side of the equation:
$y = | a - 3 |$
$y = | a + 2 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for a

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for a

4. Graph

Why learn this

Terms and topics

Related links

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