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Solution - Absolute value equations

Exact form: y=16
y=\frac{1}{6}
Decimal form: y=0.167
y=0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9y2|=|9y+1|
without the absolute value bars:

|x|=|y||9y2|=|9y+1|
x=+y(9y2)=(9y+1)
x=y(9y2)=(9y+1)
+x=y(9y2)=(9y+1)
x=y(9y2)=(9y+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9y2|=|9y+1|
x=+y , +x=y(9y2)=(9y+1)
x=y , x=y(9y2)=(9y+1)

2. Solve the two equations for y

11 additional steps

(9y-2)=(-9y+1)

Add to both sides:

(9y-2)+9y=(-9y+1)+9y

Group like terms:

(9y+9y)-2=(-9y+1)+9y

Simplify the arithmetic:

18y-2=(-9y+1)+9y

Group like terms:

18y-2=(-9y+9y)+1

Simplify the arithmetic:

18y2=1

Add to both sides:

(18y-2)+2=1+2

Simplify the arithmetic:

18y=1+2

Simplify the arithmetic:

18y=3

Divide both sides by :

(18y)18=318

Simplify the fraction:

y=318

Find the greatest common factor of the numerator and denominator:

y=(1·3)(6·3)

Factor out and cancel the greatest common factor:

y=16

6 additional steps

(9y-2)=-(-9y+1)

Expand the parentheses:

(9y-2)=9y-1

Subtract from both sides:

(9y-2)-9y=(9y-1)-9y

Group like terms:

(9y-9y)-2=(9y-1)-9y

Simplify the arithmetic:

-2=(9y-1)-9y

Group like terms:

-2=(9y-9y)-1

Simplify the arithmetic:

2=1

The statement is false:

2=1

The equation is false so it has no solution.

3. List the solutions

y=16
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9y2|
y=|9y+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.