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Solution - Absolute value equations

Exact form: x=6,-47
x=6 , -\frac{4}{7}
Decimal form: x=6,0.571
x=6 , -0.571

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x8|=|5x+16|
without the absolute value bars:

|x|=|y||9x8|=|5x+16|
x=+y(9x8)=(5x+16)
x=y(9x8)=(5x+16)
+x=y(9x8)=(5x+16)
x=y(9x8)=(5x+16)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x8|=|5x+16|
x=+y , +x=y(9x8)=(5x+16)
x=y , x=y(9x8)=(5x+16)

2. Solve the two equations for x

11 additional steps

(9x-8)=(5x+16)

Subtract from both sides:

(9x-8)-5x=(5x+16)-5x

Group like terms:

(9x-5x)-8=(5x+16)-5x

Simplify the arithmetic:

4x-8=(5x+16)-5x

Group like terms:

4x-8=(5x-5x)+16

Simplify the arithmetic:

4x8=16

Add to both sides:

(4x-8)+8=16+8

Simplify the arithmetic:

4x=16+8

Simplify the arithmetic:

4x=24

Divide both sides by :

(4x)4=244

Simplify the fraction:

x=244

Find the greatest common factor of the numerator and denominator:

x=(6·4)(1·4)

Factor out and cancel the greatest common factor:

x=6

12 additional steps

(9x-8)=-(5x+16)

Expand the parentheses:

(9x-8)=-5x-16

Add to both sides:

(9x-8)+5x=(-5x-16)+5x

Group like terms:

(9x+5x)-8=(-5x-16)+5x

Simplify the arithmetic:

14x-8=(-5x-16)+5x

Group like terms:

14x-8=(-5x+5x)-16

Simplify the arithmetic:

14x8=16

Add to both sides:

(14x-8)+8=-16+8

Simplify the arithmetic:

14x=16+8

Simplify the arithmetic:

14x=8

Divide both sides by :

(14x)14=-814

Simplify the fraction:

x=-814

Find the greatest common factor of the numerator and denominator:

x=(-4·2)(7·2)

Factor out and cancel the greatest common factor:

x=-47

3. List the solutions

x=6,-47
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9x8|
y=|5x+16|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.