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Solution - Absolute value equations

Exact form: x=3,17
x=3 , \frac{1}{7}
Decimal form: x=3,0.143
x=3 , 0.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x7|=|5x+5|
without the absolute value bars:

|x|=|y||9x7|=|5x+5|
x=+y(9x7)=(5x+5)
x=y(9x7)=(5x+5)
+x=y(9x7)=(5x+5)
x=y(9x7)=(5x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x7|=|5x+5|
x=+y , +x=y(9x7)=(5x+5)
x=y , x=y(9x7)=(5x+5)

2. Solve the two equations for x

11 additional steps

(9x-7)=(5x+5)

Subtract from both sides:

(9x-7)-5x=(5x+5)-5x

Group like terms:

(9x-5x)-7=(5x+5)-5x

Simplify the arithmetic:

4x-7=(5x+5)-5x

Group like terms:

4x-7=(5x-5x)+5

Simplify the arithmetic:

4x7=5

Add to both sides:

(4x-7)+7=5+7

Simplify the arithmetic:

4x=5+7

Simplify the arithmetic:

4x=12

Divide both sides by :

(4x)4=124

Simplify the fraction:

x=124

Find the greatest common factor of the numerator and denominator:

x=(3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(9x-7)=-(5x+5)

Expand the parentheses:

(9x-7)=-5x-5

Add to both sides:

(9x-7)+5x=(-5x-5)+5x

Group like terms:

(9x+5x)-7=(-5x-5)+5x

Simplify the arithmetic:

14x-7=(-5x-5)+5x

Group like terms:

14x-7=(-5x+5x)-5

Simplify the arithmetic:

14x7=5

Add to both sides:

(14x-7)+7=-5+7

Simplify the arithmetic:

14x=5+7

Simplify the arithmetic:

14x=2

Divide both sides by :

(14x)14=214

Simplify the fraction:

x=214

Find the greatest common factor of the numerator and denominator:

x=(1·2)(7·2)

Factor out and cancel the greatest common factor:

x=17

3. List the solutions

x=3,17
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9x7|
y=|5x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.