Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=5,-57
x=5 , -\frac{5}{7}
Decimal form: x=5,0.714
x=5 , -0.714

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x5|=|5x+15|
without the absolute value bars:

|x|=|y||9x5|=|5x+15|
x=+y(9x5)=(5x+15)
x=y(9x5)=(5x+15)
+x=y(9x5)=(5x+15)
x=y(9x5)=(5x+15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x5|=|5x+15|
x=+y , +x=y(9x5)=(5x+15)
x=y , x=y(9x5)=(5x+15)

2. Solve the two equations for x

11 additional steps

(9x-5)=(5x+15)

Subtract from both sides:

(9x-5)-5x=(5x+15)-5x

Group like terms:

(9x-5x)-5=(5x+15)-5x

Simplify the arithmetic:

4x-5=(5x+15)-5x

Group like terms:

4x-5=(5x-5x)+15

Simplify the arithmetic:

4x5=15

Add to both sides:

(4x-5)+5=15+5

Simplify the arithmetic:

4x=15+5

Simplify the arithmetic:

4x=20

Divide both sides by :

(4x)4=204

Simplify the fraction:

x=204

Find the greatest common factor of the numerator and denominator:

x=(5·4)(1·4)

Factor out and cancel the greatest common factor:

x=5

12 additional steps

(9x-5)=-(5x+15)

Expand the parentheses:

(9x-5)=-5x-15

Add to both sides:

(9x-5)+5x=(-5x-15)+5x

Group like terms:

(9x+5x)-5=(-5x-15)+5x

Simplify the arithmetic:

14x-5=(-5x-15)+5x

Group like terms:

14x-5=(-5x+5x)-15

Simplify the arithmetic:

14x5=15

Add to both sides:

(14x-5)+5=-15+5

Simplify the arithmetic:

14x=15+5

Simplify the arithmetic:

14x=10

Divide both sides by :

(14x)14=-1014

Simplify the fraction:

x=-1014

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(7·2)

Factor out and cancel the greatest common factor:

x=-57

3. List the solutions

x=5,-57
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9x5|
y=|5x+15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.