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Solution - Absolute value equations

Exact form: x=133,-16
x=\frac{13}{3} , -\frac{1}{6}
Mixed number form: x=413,-16
x=4\frac{1}{3} , -\frac{1}{6}
Decimal form: x=4.333,0.167
x=4.333 , -0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x12|=|3x+14|
without the absolute value bars:

|x|=|y||9x12|=|3x+14|
x=+y(9x12)=(3x+14)
x=y(9x12)=(3x+14)
+x=y(9x12)=(3x+14)
x=y(9x12)=(3x+14)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x12|=|3x+14|
x=+y , +x=y(9x12)=(3x+14)
x=y , x=y(9x12)=(3x+14)

2. Solve the two equations for x

11 additional steps

(9x-12)=(3x+14)

Subtract from both sides:

(9x-12)-3x=(3x+14)-3x

Group like terms:

(9x-3x)-12=(3x+14)-3x

Simplify the arithmetic:

6x-12=(3x+14)-3x

Group like terms:

6x-12=(3x-3x)+14

Simplify the arithmetic:

6x12=14

Add to both sides:

(6x-12)+12=14+12

Simplify the arithmetic:

6x=14+12

Simplify the arithmetic:

6x=26

Divide both sides by :

(6x)6=266

Simplify the fraction:

x=266

Find the greatest common factor of the numerator and denominator:

x=(13·2)(3·2)

Factor out and cancel the greatest common factor:

x=133

12 additional steps

(9x-12)=-(3x+14)

Expand the parentheses:

(9x-12)=-3x-14

Add to both sides:

(9x-12)+3x=(-3x-14)+3x

Group like terms:

(9x+3x)-12=(-3x-14)+3x

Simplify the arithmetic:

12x-12=(-3x-14)+3x

Group like terms:

12x-12=(-3x+3x)-14

Simplify the arithmetic:

12x12=14

Add to both sides:

(12x-12)+12=-14+12

Simplify the arithmetic:

12x=14+12

Simplify the arithmetic:

12x=2

Divide both sides by :

(12x)12=-212

Simplify the fraction:

x=-212

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(6·2)

Factor out and cancel the greatest common factor:

x=-16

3. List the solutions

x=133,-16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9x12|
y=|3x+14|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.