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Solution - Absolute value equations

Exact form: x=-29
x=-\frac{2}{9}
Decimal form: x=0.222
x=-0.222

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x+5|=|9x1|
without the absolute value bars:

|x|=|y||9x+5|=|9x1|
x=+y(9x+5)=(9x1)
x=y(9x+5)=(9x1)
+x=y(9x+5)=(9x1)
x=y(9x+5)=(9x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x+5|=|9x1|
x=+y , +x=y(9x+5)=(9x1)
x=y , x=y(9x+5)=(9x1)

2. Solve the two equations for x

5 additional steps

(9x+5)=(9x-1)

Subtract from both sides:

(9x+5)-9x=(9x-1)-9x

Group like terms:

(9x-9x)+5=(9x-1)-9x

Simplify the arithmetic:

5=(9x-1)-9x

Group like terms:

5=(9x-9x)-1

Simplify the arithmetic:

5=1

The statement is false:

5=1

The equation is false so it has no solution.

12 additional steps

(9x+5)=-(9x-1)

Expand the parentheses:

(9x+5)=-9x+1

Add to both sides:

(9x+5)+9x=(-9x+1)+9x

Group like terms:

(9x+9x)+5=(-9x+1)+9x

Simplify the arithmetic:

18x+5=(-9x+1)+9x

Group like terms:

18x+5=(-9x+9x)+1

Simplify the arithmetic:

18x+5=1

Subtract from both sides:

(18x+5)-5=1-5

Simplify the arithmetic:

18x=15

Simplify the arithmetic:

18x=4

Divide both sides by :

(18x)18=-418

Simplify the fraction:

x=-418

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(9·2)

Factor out and cancel the greatest common factor:

x=-29

3. Graph

Each line represents the function of one side of the equation:
y=|9x+5|
y=|9x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.