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Solution - Absolute value equations

Exact form: x=-53,-13
x=-\frac{5}{3} , -\frac{1}{3}
Mixed number form: x=-123,-13
x=-1\frac{2}{3} , -\frac{1}{3}
Decimal form: x=1.667,0.333
x=-1.667 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9x+5|=|6x|
without the absolute value bars:

|x|=|y||9x+5|=|6x|
x=+y(9x+5)=(6x)
x=y(9x+5)=(6x)
+x=y(9x+5)=(6x)
x=y(9x+5)=(6x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9x+5|=|6x|
x=+y , +x=y(9x+5)=(6x)
x=y , x=y(9x+5)=(6x)

2. Solve the two equations for x

8 additional steps

(9x+5)=6x

Subtract from both sides:

(9x+5)-6x=(6x)-6x

Group like terms:

(9x-6x)+5=(6x)-6x

Simplify the arithmetic:

3x+5=(6x)-6x

Simplify the arithmetic:

3x+5=0

Subtract from both sides:

(3x+5)-5=0-5

Simplify the arithmetic:

3x=05

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=-53

Simplify the fraction:

x=-53

9 additional steps

(9x+5)=-6x

Subtract from both sides:

(9x+5)-5=(-6x)-5

Simplify the arithmetic:

9x=(-6x)-5

Add to both sides:

(9x)+6x=((-6x)-5)+6x

Simplify the arithmetic:

15x=((-6x)-5)+6x

Group like terms:

15x=(-6x+6x)-5

Simplify the arithmetic:

15x=5

Divide both sides by :

(15x)15=-515

Simplify the fraction:

x=-515

Find the greatest common factor of the numerator and denominator:

x=(-1·5)(3·5)

Factor out and cancel the greatest common factor:

x=-13

3. List the solutions

x=-53,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9x+5|
y=|6x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.