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Solution - Absolute value equations

Exact form: w=2,-611
w=2 , -\frac{6}{11}
Decimal form: w=2,0.545
w=2 , -0.545

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9w4|=|2w+10|
without the absolute value bars:

|x|=|y||9w4|=|2w+10|
x=+y(9w4)=(2w+10)
x=y(9w4)=(2w+10)
+x=y(9w4)=(2w+10)
x=y(9w4)=(2w+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9w4|=|2w+10|
x=+y , +x=y(9w4)=(2w+10)
x=y , x=y(9w4)=(2w+10)

2. Solve the two equations for w

11 additional steps

(9w-4)=(2w+10)

Subtract from both sides:

(9w-4)-2w=(2w+10)-2w

Group like terms:

(9w-2w)-4=(2w+10)-2w

Simplify the arithmetic:

7w-4=(2w+10)-2w

Group like terms:

7w-4=(2w-2w)+10

Simplify the arithmetic:

7w4=10

Add to both sides:

(7w-4)+4=10+4

Simplify the arithmetic:

7w=10+4

Simplify the arithmetic:

7w=14

Divide both sides by :

(7w)7=147

Simplify the fraction:

w=147

Find the greatest common factor of the numerator and denominator:

w=(2·7)(1·7)

Factor out and cancel the greatest common factor:

w=2

10 additional steps

(9w-4)=-(2w+10)

Expand the parentheses:

(9w-4)=-2w-10

Add to both sides:

(9w-4)+2w=(-2w-10)+2w

Group like terms:

(9w+2w)-4=(-2w-10)+2w

Simplify the arithmetic:

11w-4=(-2w-10)+2w

Group like terms:

11w-4=(-2w+2w)-10

Simplify the arithmetic:

11w4=10

Add to both sides:

(11w-4)+4=-10+4

Simplify the arithmetic:

11w=10+4

Simplify the arithmetic:

11w=6

Divide both sides by :

(11w)11=-611

Simplify the fraction:

w=-611

3. List the solutions

w=2,-611
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|9w4|
y=|2w+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.