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Solution - Absolute value equations

Exact form: i=1243,-1225
i=\frac{12}{43} , -\frac{12}{25}
Decimal form: i=0.279,0.48
i=0.279 , -0.48

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|9i12|+|34i|=0

Add |34i| to both sides of the equation:

|9i12|+|34i||34i|=|34i|

Simplify the arithmetic

|9i12|=|34i|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|9i12|=|34i|
without the absolute value bars:

|x|=|y||9i12|=|34i|
x=+y(9i12)=(34i)
x=y(9i12)=(34i)
+x=y(9i12)=(34i)
x=y(9i12)=(34i)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||9i12|=|34i|
x=+y , +x=y(9i12)=(34i)
x=y , x=y(9i12)=(34i)

3. Solve the two equations for i

7 additional steps

(9i-12)=-34i

Add to both sides:

(9i-12)+12=(-34i)+12

Simplify the arithmetic:

9i=(-34i)+12

Add to both sides:

(9i)+34i=((-34i)+12)+34i

Simplify the arithmetic:

43i=((-34i)+12)+34i

Group like terms:

43i=(-34i+34i)+12

Simplify the arithmetic:

43i=12

Divide both sides by :

(43i)43=1243

Simplify the fraction:

i=1243

12 additional steps

(9i-12)=--34i

Group like terms:

(9i-12)=(-1·-34)i

Multiply the coefficients:

(9i-12)=34i

Subtract from both sides:

(9i-12)-34i=(34i)-34i

Group like terms:

(9i-34i)-12=(34i)-34i

Simplify the arithmetic:

-25i-12=(34i)-34i

Simplify the arithmetic:

25i12=0

Add to both sides:

(-25i-12)+12=0+12

Simplify the arithmetic:

25i=0+12

Simplify the arithmetic:

25i=12

Divide both sides by :

(-25i)-25=12-25

Cancel out the negatives:

25i25=12-25

Simplify the fraction:

i=12-25

Move the negative sign from the denominator to the numerator:

i=-1225

4. List the solutions

i=1243,-1225
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|9i12|
y=|34i|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.