Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: a=1
a=1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5a+9|=|5a+1|
without the absolute value bars:

|x|=|y||5a+9|=|5a+1|
x=+y(5a+9)=(5a+1)
x=y(5a+9)=(5a+1)
+x=y(5a+9)=(5a+1)
x=y(5a+9)=(5a+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5a+9|=|5a+1|
x=+y , +x=y(5a+9)=(5a+1)
x=y , x=y(5a+9)=(5a+1)

2. Solve the two equations for a

5 additional steps

(-5a+9)=(-5a+1)

Add to both sides:

(-5a+9)+5a=(-5a+1)+5a

Group like terms:

(-5a+5a)+9=(-5a+1)+5a

Simplify the arithmetic:

9=(-5a+1)+5a

Group like terms:

9=(-5a+5a)+1

Simplify the arithmetic:

9=1

The statement is false:

9=1

The equation is false so it has no solution.

13 additional steps

(-5a+9)=-(-5a+1)

Expand the parentheses:

(-5a+9)=5a-1

Subtract from both sides:

(-5a+9)-5a=(5a-1)-5a

Group like terms:

(-5a-5a)+9=(5a-1)-5a

Simplify the arithmetic:

-10a+9=(5a-1)-5a

Group like terms:

-10a+9=(5a-5a)-1

Simplify the arithmetic:

10a+9=1

Subtract from both sides:

(-10a+9)-9=-1-9

Simplify the arithmetic:

10a=19

Simplify the arithmetic:

10a=10

Divide both sides by :

(-10a)-10=-10-10

Cancel out the negatives:

10a10=-10-10

Simplify the fraction:

a=-10-10

Cancel out the negatives:

a=1010

Simplify the fraction:

a=1

3. Graph

Each line represents the function of one side of the equation:
y=|5a+9|
y=|5a+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.