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Solution - Absolute value equations

Exact form: x=2,0
x=2 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x5|=|3x+5|
without the absolute value bars:

|x|=|y||8x5|=|3x+5|
x=+y(8x5)=(3x+5)
x=y(8x5)=(3x+5)
+x=y(8x5)=(3x+5)
x=y(8x5)=(3x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x5|=|3x+5|
x=+y , +x=y(8x5)=(3x+5)
x=y , x=y(8x5)=(3x+5)

2. Solve the two equations for x

11 additional steps

(8x-5)=(3x+5)

Subtract from both sides:

(8x-5)-3x=(3x+5)-3x

Group like terms:

(8x-3x)-5=(3x+5)-3x

Simplify the arithmetic:

5x-5=(3x+5)-3x

Group like terms:

5x-5=(3x-3x)+5

Simplify the arithmetic:

5x5=5

Add to both sides:

(5x-5)+5=5+5

Simplify the arithmetic:

5x=5+5

Simplify the arithmetic:

5x=10

Divide both sides by :

(5x)5=105

Simplify the fraction:

x=105

Find the greatest common factor of the numerator and denominator:

x=(2·5)(1·5)

Factor out and cancel the greatest common factor:

x=2

9 additional steps

(8x-5)=-(3x+5)

Expand the parentheses:

(8x-5)=-3x-5

Add to both sides:

(8x-5)+3x=(-3x-5)+3x

Group like terms:

(8x+3x)-5=(-3x-5)+3x

Simplify the arithmetic:

11x-5=(-3x-5)+3x

Group like terms:

11x-5=(-3x+3x)-5

Simplify the arithmetic:

11x5=5

Add to both sides:

(11x-5)+5=-5+5

Simplify the arithmetic:

11x=5+5

Simplify the arithmetic:

11x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=2,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x5|
y=|3x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.