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Solution - Absolute value equations

Exact form: x=92,-76
x=\frac{9}{2} , -\frac{7}{6}
Mixed number form: x=412,-116
x=4\frac{1}{2} , -1\frac{1}{6}
Decimal form: x=4.5,1.167
x=4.5 , -1.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x2|=|4x+16|
without the absolute value bars:

|x|=|y||8x2|=|4x+16|
x=+y(8x2)=(4x+16)
x=y(8x2)=(4x+16)
+x=y(8x2)=(4x+16)
x=y(8x2)=(4x+16)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x2|=|4x+16|
x=+y , +x=y(8x2)=(4x+16)
x=y , x=y(8x2)=(4x+16)

2. Solve the two equations for x

11 additional steps

(8x-2)=(4x+16)

Subtract from both sides:

(8x-2)-4x=(4x+16)-4x

Group like terms:

(8x-4x)-2=(4x+16)-4x

Simplify the arithmetic:

4x-2=(4x+16)-4x

Group like terms:

4x-2=(4x-4x)+16

Simplify the arithmetic:

4x2=16

Add to both sides:

(4x-2)+2=16+2

Simplify the arithmetic:

4x=16+2

Simplify the arithmetic:

4x=18

Divide both sides by :

(4x)4=184

Simplify the fraction:

x=184

Find the greatest common factor of the numerator and denominator:

x=(9·2)(2·2)

Factor out and cancel the greatest common factor:

x=92

12 additional steps

(8x-2)=-(4x+16)

Expand the parentheses:

(8x-2)=-4x-16

Add to both sides:

(8x-2)+4x=(-4x-16)+4x

Group like terms:

(8x+4x)-2=(-4x-16)+4x

Simplify the arithmetic:

12x-2=(-4x-16)+4x

Group like terms:

12x-2=(-4x+4x)-16

Simplify the arithmetic:

12x2=16

Add to both sides:

(12x-2)+2=-16+2

Simplify the arithmetic:

12x=16+2

Simplify the arithmetic:

12x=14

Divide both sides by :

(12x)12=-1412

Simplify the fraction:

x=-1412

Find the greatest common factor of the numerator and denominator:

x=(-7·2)(6·2)

Factor out and cancel the greatest common factor:

x=-76

3. List the solutions

x=92,-76
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x2|
y=|4x+16|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.