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Solution - Absolute value equations

Exact form: x=185,-1411
x=\frac{18}{5} , -\frac{14}{11}
Mixed number form: x=335,-1311
x=3\frac{3}{5} , -1\frac{3}{11}
Decimal form: x=3.6,1.273
x=3.6 , -1.273

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x2|=|3x+16|
without the absolute value bars:

|x|=|y||8x2|=|3x+16|
x=+y(8x2)=(3x+16)
x=y(8x2)=(3x+16)
+x=y(8x2)=(3x+16)
x=y(8x2)=(3x+16)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x2|=|3x+16|
x=+y , +x=y(8x2)=(3x+16)
x=y , x=y(8x2)=(3x+16)

2. Solve the two equations for x

9 additional steps

(8x-2)=(3x+16)

Subtract from both sides:

(8x-2)-3x=(3x+16)-3x

Group like terms:

(8x-3x)-2=(3x+16)-3x

Simplify the arithmetic:

5x-2=(3x+16)-3x

Group like terms:

5x-2=(3x-3x)+16

Simplify the arithmetic:

5x2=16

Add to both sides:

(5x-2)+2=16+2

Simplify the arithmetic:

5x=16+2

Simplify the arithmetic:

5x=18

Divide both sides by :

(5x)5=185

Simplify the fraction:

x=185

10 additional steps

(8x-2)=-(3x+16)

Expand the parentheses:

(8x-2)=-3x-16

Add to both sides:

(8x-2)+3x=(-3x-16)+3x

Group like terms:

(8x+3x)-2=(-3x-16)+3x

Simplify the arithmetic:

11x-2=(-3x-16)+3x

Group like terms:

11x-2=(-3x+3x)-16

Simplify the arithmetic:

11x2=16

Add to both sides:

(11x-2)+2=-16+2

Simplify the arithmetic:

11x=16+2

Simplify the arithmetic:

11x=14

Divide both sides by :

(11x)11=-1411

Simplify the fraction:

x=-1411

3. List the solutions

x=185,-1411
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x2|
y=|3x+16|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.