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Solution - Absolute value equations

Exact form: x=152,23
x=\frac{15}{2} , \frac{2}{3}
Mixed number form: x=712,23
x=7\frac{1}{2} , \frac{2}{3}
Decimal form: x=7.5,0.667
x=7.5 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x19|=|4x+11|
without the absolute value bars:

|x|=|y||8x19|=|4x+11|
x=+y(8x19)=(4x+11)
x=y(8x19)=(4x+11)
+x=y(8x19)=(4x+11)
x=y(8x19)=(4x+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x19|=|4x+11|
x=+y , +x=y(8x19)=(4x+11)
x=y , x=y(8x19)=(4x+11)

2. Solve the two equations for x

11 additional steps

(8x-19)=(4x+11)

Subtract from both sides:

(8x-19)-4x=(4x+11)-4x

Group like terms:

(8x-4x)-19=(4x+11)-4x

Simplify the arithmetic:

4x-19=(4x+11)-4x

Group like terms:

4x-19=(4x-4x)+11

Simplify the arithmetic:

4x19=11

Add to both sides:

(4x-19)+19=11+19

Simplify the arithmetic:

4x=11+19

Simplify the arithmetic:

4x=30

Divide both sides by :

(4x)4=304

Simplify the fraction:

x=304

Find the greatest common factor of the numerator and denominator:

x=(15·2)(2·2)

Factor out and cancel the greatest common factor:

x=152

12 additional steps

(8x-19)=-(4x+11)

Expand the parentheses:

(8x-19)=-4x-11

Add to both sides:

(8x-19)+4x=(-4x-11)+4x

Group like terms:

(8x+4x)-19=(-4x-11)+4x

Simplify the arithmetic:

12x-19=(-4x-11)+4x

Group like terms:

12x-19=(-4x+4x)-11

Simplify the arithmetic:

12x19=11

Add to both sides:

(12x-19)+19=-11+19

Simplify the arithmetic:

12x=11+19

Simplify the arithmetic:

12x=8

Divide both sides by :

(12x)12=812

Simplify the fraction:

x=812

Find the greatest common factor of the numerator and denominator:

x=(2·4)(3·4)

Factor out and cancel the greatest common factor:

x=23

3. List the solutions

x=152,23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x19|
y=|4x+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.