Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=4,1
x=4 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x17|=|2x+7|
without the absolute value bars:

|x|=|y||8x17|=|2x+7|
x=+y(8x17)=(2x+7)
x=y(8x17)=(2x+7)
+x=y(8x17)=(2x+7)
x=y(8x17)=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x17|=|2x+7|
x=+y , +x=y(8x17)=(2x+7)
x=y , x=y(8x17)=(2x+7)

2. Solve the two equations for x

11 additional steps

(8x-17)=(2x+7)

Subtract from both sides:

(8x-17)-2x=(2x+7)-2x

Group like terms:

(8x-2x)-17=(2x+7)-2x

Simplify the arithmetic:

6x-17=(2x+7)-2x

Group like terms:

6x-17=(2x-2x)+7

Simplify the arithmetic:

6x17=7

Add to both sides:

(6x-17)+17=7+17

Simplify the arithmetic:

6x=7+17

Simplify the arithmetic:

6x=24

Divide both sides by :

(6x)6=246

Simplify the fraction:

x=246

Find the greatest common factor of the numerator and denominator:

x=(4·6)(1·6)

Factor out and cancel the greatest common factor:

x=4

11 additional steps

(8x-17)=-(2x+7)

Expand the parentheses:

(8x-17)=-2x-7

Add to both sides:

(8x-17)+2x=(-2x-7)+2x

Group like terms:

(8x+2x)-17=(-2x-7)+2x

Simplify the arithmetic:

10x-17=(-2x-7)+2x

Group like terms:

10x-17=(-2x+2x)-7

Simplify the arithmetic:

10x17=7

Add to both sides:

(10x-17)+17=-7+17

Simplify the arithmetic:

10x=7+17

Simplify the arithmetic:

10x=10

Divide both sides by :

(10x)10=1010

Simplify the fraction:

x=1010

Simplify the fraction:

x=1

3. List the solutions

x=4,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x17|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.