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Solution - Absolute value equations

Exact form: x=165,1611
x=\frac{16}{5} , \frac{16}{11}
Mixed number form: x=315,1511
x=3\frac{1}{5} , 1\frac{5}{11}
Decimal form: x=3.2,1.455
x=3.2 , 1.455

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x16|=|3x|
without the absolute value bars:

|x|=|y||8x16|=|3x|
x=+y(8x16)=(3x)
x=y(8x16)=(3x)
+x=y(8x16)=(3x)
x=y(8x16)=(3x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x16|=|3x|
x=+y , +x=y(8x16)=(3x)
x=y , x=y(8x16)=(3x)

2. Solve the two equations for x

8 additional steps

(8x-16)=3x

Subtract from both sides:

(8x-16)-3x=(3x)-3x

Group like terms:

(8x-3x)-16=(3x)-3x

Simplify the arithmetic:

5x-16=(3x)-3x

Simplify the arithmetic:

5x16=0

Add to both sides:

(5x-16)+16=0+16

Simplify the arithmetic:

5x=0+16

Simplify the arithmetic:

5x=16

Divide both sides by :

(5x)5=165

Simplify the fraction:

x=165

7 additional steps

(8x-16)=-3x

Add to both sides:

(8x-16)+16=(-3x)+16

Simplify the arithmetic:

8x=(-3x)+16

Add to both sides:

(8x)+3x=((-3x)+16)+3x

Simplify the arithmetic:

11x=((-3x)+16)+3x

Group like terms:

11x=(-3x+3x)+16

Simplify the arithmetic:

11x=16

Divide both sides by :

(11x)11=1611

Simplify the fraction:

x=1611

3. List the solutions

x=165,1611
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x16|
y=|3x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.