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Solution - Absolute value equations

Exact form: x=163,1213
x=\frac{16}{3} , \frac{12}{13}
Mixed number form: x=513,1213
x=5\frac{1}{3} , \frac{12}{13}
Decimal form: x=5.333,0.923
x=5.333 , 0.923

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x14|=|5x+2|
without the absolute value bars:

|x|=|y||8x14|=|5x+2|
x=+y(8x14)=(5x+2)
x=y(8x14)=(5x+2)
+x=y(8x14)=(5x+2)
x=y(8x14)=(5x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x14|=|5x+2|
x=+y , +x=y(8x14)=(5x+2)
x=y , x=y(8x14)=(5x+2)

2. Solve the two equations for x

9 additional steps

(8x-14)=(5x+2)

Subtract from both sides:

(8x-14)-5x=(5x+2)-5x

Group like terms:

(8x-5x)-14=(5x+2)-5x

Simplify the arithmetic:

3x-14=(5x+2)-5x

Group like terms:

3x-14=(5x-5x)+2

Simplify the arithmetic:

3x14=2

Add to both sides:

(3x-14)+14=2+14

Simplify the arithmetic:

3x=2+14

Simplify the arithmetic:

3x=16

Divide both sides by :

(3x)3=163

Simplify the fraction:

x=163

10 additional steps

(8x-14)=-(5x+2)

Expand the parentheses:

(8x-14)=-5x-2

Add to both sides:

(8x-14)+5x=(-5x-2)+5x

Group like terms:

(8x+5x)-14=(-5x-2)+5x

Simplify the arithmetic:

13x-14=(-5x-2)+5x

Group like terms:

13x-14=(-5x+5x)-2

Simplify the arithmetic:

13x14=2

Add to both sides:

(13x-14)+14=-2+14

Simplify the arithmetic:

13x=2+14

Simplify the arithmetic:

13x=12

Divide both sides by :

(13x)13=1213

Simplify the fraction:

x=1213

3. List the solutions

x=163,1213
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x14|
y=|5x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.