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Solution - Absolute value equations

Exact form: x=116,-910
x=\frac{11}{6} , -\frac{9}{10}
Mixed number form: x=156,-910
x=1\frac{5}{6} , -\frac{9}{10}
Decimal form: x=1.833,0.9
x=1.833 , -0.9

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x1|=|2x+10|
without the absolute value bars:

|x|=|y||8x1|=|2x+10|
x=+y(8x1)=(2x+10)
x=y(8x1)=(2x+10)
+x=y(8x1)=(2x+10)
x=y(8x1)=(2x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x1|=|2x+10|
x=+y , +x=y(8x1)=(2x+10)
x=y , x=y(8x1)=(2x+10)

2. Solve the two equations for x

9 additional steps

(8x-1)=(2x+10)

Subtract from both sides:

(8x-1)-2x=(2x+10)-2x

Group like terms:

(8x-2x)-1=(2x+10)-2x

Simplify the arithmetic:

6x-1=(2x+10)-2x

Group like terms:

6x-1=(2x-2x)+10

Simplify the arithmetic:

6x1=10

Add to both sides:

(6x-1)+1=10+1

Simplify the arithmetic:

6x=10+1

Simplify the arithmetic:

6x=11

Divide both sides by :

(6x)6=116

Simplify the fraction:

x=116

10 additional steps

(8x-1)=-(2x+10)

Expand the parentheses:

(8x-1)=-2x-10

Add to both sides:

(8x-1)+2x=(-2x-10)+2x

Group like terms:

(8x+2x)-1=(-2x-10)+2x

Simplify the arithmetic:

10x-1=(-2x-10)+2x

Group like terms:

10x-1=(-2x+2x)-10

Simplify the arithmetic:

10x1=10

Add to both sides:

(10x-1)+1=-10+1

Simplify the arithmetic:

10x=10+1

Simplify the arithmetic:

10x=9

Divide both sides by :

(10x)10=-910

Simplify the fraction:

x=-910

3. List the solutions

x=116,-910
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x1|
y=|2x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.