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Solution - Absolute value equations

Exact form: x=-13,-2
x=-\frac{1}{3} , -2
Decimal form: x=0.333,2
x=-0.333 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+6|=|4x+2|
without the absolute value bars:

|x|=|y||8x+6|=|4x+2|
x=+y(8x+6)=(4x+2)
x=y(8x+6)=(4x+2)
+x=y(8x+6)=(4x+2)
x=y(8x+6)=(4x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+6|=|4x+2|
x=+y , +x=y(8x+6)=(4x+2)
x=y , x=y(8x+6)=(4x+2)

2. Solve the two equations for x

11 additional steps

(8x+6)=(-4x+2)

Add to both sides:

(8x+6)+4x=(-4x+2)+4x

Group like terms:

(8x+4x)+6=(-4x+2)+4x

Simplify the arithmetic:

12x+6=(-4x+2)+4x

Group like terms:

12x+6=(-4x+4x)+2

Simplify the arithmetic:

12x+6=2

Subtract from both sides:

(12x+6)-6=2-6

Simplify the arithmetic:

12x=26

Simplify the arithmetic:

12x=4

Divide both sides by :

(12x)12=-412

Simplify the fraction:

x=-412

Find the greatest common factor of the numerator and denominator:

x=(-1·4)(3·4)

Factor out and cancel the greatest common factor:

x=-13

12 additional steps

(8x+6)=-(-4x+2)

Expand the parentheses:

(8x+6)=4x-2

Subtract from both sides:

(8x+6)-4x=(4x-2)-4x

Group like terms:

(8x-4x)+6=(4x-2)-4x

Simplify the arithmetic:

4x+6=(4x-2)-4x

Group like terms:

4x+6=(4x-4x)-2

Simplify the arithmetic:

4x+6=2

Subtract from both sides:

(4x+6)-6=-2-6

Simplify the arithmetic:

4x=26

Simplify the arithmetic:

4x=8

Divide both sides by :

(4x)4=-84

Simplify the fraction:

x=-84

Find the greatest common factor of the numerator and denominator:

x=(-2·4)(1·4)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=-13,-2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+6|
y=|4x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.