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Solution - Absolute value equations

Exact form: x=-92,514
x=-\frac{9}{2} , \frac{5}{14}
Mixed number form: x=-412,514
x=-4\frac{1}{2} , \frac{5}{14}
Decimal form: x=4.5,0.357
x=-4.5 , 0.357

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+2|=|6x7|
without the absolute value bars:

|x|=|y||8x+2|=|6x7|
x=+y(8x+2)=(6x7)
x=y(8x+2)=(6x7)
+x=y(8x+2)=(6x7)
x=y(8x+2)=(6x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+2|=|6x7|
x=+y , +x=y(8x+2)=(6x7)
x=y , x=y(8x+2)=(6x7)

2. Solve the two equations for x

9 additional steps

(8x+2)=(6x-7)

Subtract from both sides:

(8x+2)-6x=(6x-7)-6x

Group like terms:

(8x-6x)+2=(6x-7)-6x

Simplify the arithmetic:

2x+2=(6x-7)-6x

Group like terms:

2x+2=(6x-6x)-7

Simplify the arithmetic:

2x+2=7

Subtract from both sides:

(2x+2)-2=-7-2

Simplify the arithmetic:

2x=72

Simplify the arithmetic:

2x=9

Divide both sides by :

(2x)2=-92

Simplify the fraction:

x=-92

10 additional steps

(8x+2)=-(6x-7)

Expand the parentheses:

(8x+2)=-6x+7

Add to both sides:

(8x+2)+6x=(-6x+7)+6x

Group like terms:

(8x+6x)+2=(-6x+7)+6x

Simplify the arithmetic:

14x+2=(-6x+7)+6x

Group like terms:

14x+2=(-6x+6x)+7

Simplify the arithmetic:

14x+2=7

Subtract from both sides:

(14x+2)-2=7-2

Simplify the arithmetic:

14x=72

Simplify the arithmetic:

14x=5

Divide both sides by :

(14x)14=514

Simplify the fraction:

x=514

3. List the solutions

x=-92,514
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+2|
y=|6x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.