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Solution - Absolute value equations

Exact form: x=-292,-314
x=-\frac{29}{2} , -\frac{3}{14}
Mixed number form: x=-1412,-314
x=-14\frac{1}{2} , -\frac{3}{14}
Decimal form: x=14.5,0.214
x=-14.5 , -0.214

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+16|=|6x13|
without the absolute value bars:

|x|=|y||8x+16|=|6x13|
x=+y(8x+16)=(6x13)
x=y(8x+16)=(6x13)
+x=y(8x+16)=(6x13)
x=y(8x+16)=(6x13)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+16|=|6x13|
x=+y , +x=y(8x+16)=(6x13)
x=y , x=y(8x+16)=(6x13)

2. Solve the two equations for x

9 additional steps

(8x+16)=(6x-13)

Subtract from both sides:

(8x+16)-6x=(6x-13)-6x

Group like terms:

(8x-6x)+16=(6x-13)-6x

Simplify the arithmetic:

2x+16=(6x-13)-6x

Group like terms:

2x+16=(6x-6x)-13

Simplify the arithmetic:

2x+16=13

Subtract from both sides:

(2x+16)-16=-13-16

Simplify the arithmetic:

2x=1316

Simplify the arithmetic:

2x=29

Divide both sides by :

(2x)2=-292

Simplify the fraction:

x=-292

10 additional steps

(8x+16)=-(6x-13)

Expand the parentheses:

(8x+16)=-6x+13

Add to both sides:

(8x+16)+6x=(-6x+13)+6x

Group like terms:

(8x+6x)+16=(-6x+13)+6x

Simplify the arithmetic:

14x+16=(-6x+13)+6x

Group like terms:

14x+16=(-6x+6x)+13

Simplify the arithmetic:

14x+16=13

Subtract from both sides:

(14x+16)-16=13-16

Simplify the arithmetic:

14x=1316

Simplify the arithmetic:

14x=3

Divide both sides by :

(14x)14=-314

Simplify the fraction:

x=-314

3. List the solutions

x=-292,-314
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+16|
y=|6x13|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.