Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-112
x=-\frac{11}{2}
Mixed number form: x=-512
x=-5\frac{1}{2}
Decimal form: x=5.5
x=-5.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+8|=|x+19|
without the absolute value bars:

|x|=|y||x+8|=|x+19|
x=+y(x+8)=(x+19)
x=y(x+8)=(x+19)
+x=y(x+8)=(x+19)
x=y(x+8)=(x+19)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+8|=|x+19|
x=+y , +x=y(x+8)=(x+19)
x=y , x=y(x+8)=(x+19)

2. Solve the two equations for x

11 additional steps

(-x+8)=(x+19)

Subtract from both sides:

(-x+8)-x=(x+19)-x

Group like terms:

(-x-x)+8=(x+19)-x

Simplify the arithmetic:

-2x+8=(x+19)-x

Group like terms:

-2x+8=(x-x)+19

Simplify the arithmetic:

2x+8=19

Subtract from both sides:

(-2x+8)-8=19-8

Simplify the arithmetic:

2x=198

Simplify the arithmetic:

2x=11

Divide both sides by :

(-2x)-2=11-2

Cancel out the negatives:

2x2=11-2

Simplify the fraction:

x=11-2

Move the negative sign from the denominator to the numerator:

x=-112

6 additional steps

(-x+8)=-(x+19)

Expand the parentheses:

(-x+8)=-x-19

Add to both sides:

(-x+8)+x=(-x-19)+x

Group like terms:

(-x+x)+8=(-x-19)+x

Simplify the arithmetic:

8=(-x-19)+x

Group like terms:

8=(-x+x)-19

Simplify the arithmetic:

8=19

The statement is false:

8=19

The equation is false so it has no solution.

3. List the solutions

x=-112
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+8|
y=|x+19|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.