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Solution - Absolute value equations

Exact form: x=75,9
x=\frac{7}{5} , 9
Mixed number form: x=125,9
x=1\frac{2}{5} , 9
Decimal form: x=1.4,9
x=1.4 , 9

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+8|=|2x+1|
without the absolute value bars:

|x|=|y||3x+8|=|2x+1|
x=+y(3x+8)=(2x+1)
x=y(3x+8)=(2x+1)
+x=y(3x+8)=(2x+1)
x=y(3x+8)=(2x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+8|=|2x+1|
x=+y , +x=y(3x+8)=(2x+1)
x=y , x=y(3x+8)=(2x+1)

2. Solve the two equations for x

11 additional steps

(-3x+8)=(2x+1)

Subtract from both sides:

(-3x+8)-2x=(2x+1)-2x

Group like terms:

(-3x-2x)+8=(2x+1)-2x

Simplify the arithmetic:

-5x+8=(2x+1)-2x

Group like terms:

-5x+8=(2x-2x)+1

Simplify the arithmetic:

5x+8=1

Subtract from both sides:

(-5x+8)-8=1-8

Simplify the arithmetic:

5x=18

Simplify the arithmetic:

5x=7

Divide both sides by :

(-5x)-5=-7-5

Cancel out the negatives:

5x5=-7-5

Simplify the fraction:

x=-7-5

Cancel out the negatives:

x=75

11 additional steps

(-3x+8)=-(2x+1)

Expand the parentheses:

(-3x+8)=-2x-1

Add to both sides:

(-3x+8)+2x=(-2x-1)+2x

Group like terms:

(-3x+2x)+8=(-2x-1)+2x

Simplify the arithmetic:

-x+8=(-2x-1)+2x

Group like terms:

-x+8=(-2x+2x)-1

Simplify the arithmetic:

x+8=1

Subtract from both sides:

(-x+8)-8=-1-8

Simplify the arithmetic:

x=18

Simplify the arithmetic:

x=9

Multiply both sides by :

-x·-1=-9·-1

Remove the one(s):

x=-9·-1

Simplify the arithmetic:

x=9

3. List the solutions

x=75,9
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+8|
y=|2x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.