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Solution - Absolute value equations

Exact form: x=4,8
x=4 , 8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+8|=2|x4|
without the absolute value bars:

|x|=|y||2x+8|=2|x4|
x=+y(2x+8)=2(x4)
x=y(2x+8)=2((x4))
+x=y(2x+8)=2(x4)
x=y(2x+8)=2(x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+8|=2|x4|
x=+y , +x=y(2x+8)=2(x4)
x=y , x=y(2x+8)=2((x4))

2. Solve the two equations for x

15 additional steps

(-2x+8)=2·(x-4)

Expand the parentheses:

(-2x+8)=2x+2·-4

Simplify the arithmetic:

(-2x+8)=2x-8

Subtract from both sides:

(-2x+8)-2x=(2x-8)-2x

Group like terms:

(-2x-2x)+8=(2x-8)-2x

Simplify the arithmetic:

-4x+8=(2x-8)-2x

Group like terms:

-4x+8=(2x-2x)-8

Simplify the arithmetic:

4x+8=8

Subtract from both sides:

(-4x+8)-8=-8-8

Simplify the arithmetic:

4x=88

Simplify the arithmetic:

4x=16

Divide both sides by :

(-4x)-4=-16-4

Cancel out the negatives:

4x4=-16-4

Simplify the fraction:

x=-16-4

Cancel out the negatives:

x=164

Find the greatest common factor of the numerator and denominator:

x=(4·4)(1·4)

Factor out and cancel the greatest common factor:

x=4

9 additional steps

(-2x+8)=2·(-(x-4))

Expand the parentheses:

(-2x+8)=2·(-x+4)

(-2x+8)=2·-x+2·4

Group like terms:

(-2x+8)=(2·-1)x+2·4

Multiply the coefficients:

(-2x+8)=-2x+2·4

Simplify the arithmetic:

(-2x+8)=-2x+8

Add to both sides:

(-2x+8)+2x=(-2x+8)+2x

Group like terms:

(-2x+2x)+8=(-2x+8)+2x

Simplify the arithmetic:

8=(-2x+8)+2x

Group like terms:

8=(-2x+2x)+8

Simplify the arithmetic:

8=8

3. List the solutions

x=4,8
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+8|
y=2|x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.