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Solution - Absolute value equations

Exact form: x=12,613
x=12 , \frac{6}{13}
Decimal form: x=12,0.462
x=12 , 0.462

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x9|=|6x+3|
without the absolute value bars:

|x|=|y||7x9|=|6x+3|
x=+y(7x9)=(6x+3)
x=y(7x9)=(6x+3)
+x=y(7x9)=(6x+3)
x=y(7x9)=(6x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x9|=|6x+3|
x=+y , +x=y(7x9)=(6x+3)
x=y , x=y(7x9)=(6x+3)

2. Solve the two equations for x

7 additional steps

(7x-9)=(6x+3)

Subtract from both sides:

(7x-9)-6x=(6x+3)-6x

Group like terms:

(7x-6x)-9=(6x+3)-6x

Simplify the arithmetic:

x-9=(6x+3)-6x

Group like terms:

x-9=(6x-6x)+3

Simplify the arithmetic:

x9=3

Add to both sides:

(x-9)+9=3+9

Simplify the arithmetic:

x=3+9

Simplify the arithmetic:

x=12

10 additional steps

(7x-9)=-(6x+3)

Expand the parentheses:

(7x-9)=-6x-3

Add to both sides:

(7x-9)+6x=(-6x-3)+6x

Group like terms:

(7x+6x)-9=(-6x-3)+6x

Simplify the arithmetic:

13x-9=(-6x-3)+6x

Group like terms:

13x-9=(-6x+6x)-3

Simplify the arithmetic:

13x9=3

Add to both sides:

(13x-9)+9=-3+9

Simplify the arithmetic:

13x=3+9

Simplify the arithmetic:

13x=6

Divide both sides by :

(13x)13=613

Simplify the fraction:

x=613

3. List the solutions

x=12,613
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x9|
y=|6x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.