Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-1,32
x=-1 , \frac{3}{2}
Mixed number form: x=-1,112
x=-1 , 1\frac{1}{2}
Decimal form: x=1,1.5
x=-1 , 1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x3|=|x9|
without the absolute value bars:

|x|=|y||7x3|=|x9|
x=+y(7x3)=(x9)
x=y(7x3)=(x9)
+x=y(7x3)=(x9)
x=y(7x3)=(x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x3|=|x9|
x=+y , +x=y(7x3)=(x9)
x=y , x=y(7x3)=(x9)

2. Solve the two equations for x

10 additional steps

(7x-3)=(x-9)

Subtract from both sides:

(7x-3)-x=(x-9)-x

Group like terms:

(7x-x)-3=(x-9)-x

Simplify the arithmetic:

6x-3=(x-9)-x

Group like terms:

6x-3=(x-x)-9

Simplify the arithmetic:

6x3=9

Add to both sides:

(6x-3)+3=-9+3

Simplify the arithmetic:

6x=9+3

Simplify the arithmetic:

6x=6

Divide both sides by :

(6x)6=-66

Simplify the fraction:

x=-66

Simplify the fraction:

x=1

12 additional steps

(7x-3)=-(x-9)

Expand the parentheses:

(7x-3)=-x+9

Add to both sides:

(7x-3)+x=(-x+9)+x

Group like terms:

(7x+x)-3=(-x+9)+x

Simplify the arithmetic:

8x-3=(-x+9)+x

Group like terms:

8x-3=(-x+x)+9

Simplify the arithmetic:

8x3=9

Add to both sides:

(8x-3)+3=9+3

Simplify the arithmetic:

8x=9+3

Simplify the arithmetic:

8x=12

Divide both sides by :

(8x)8=128

Simplify the fraction:

x=128

Find the greatest common factor of the numerator and denominator:

x=(3·4)(2·4)

Factor out and cancel the greatest common factor:

x=32

3. List the solutions

x=-1,32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x3|
y=|x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.