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Solution - Absolute value equations

Exact form: x=12,512
x=\frac{1}{2} , \frac{5}{12}
Decimal form: x=0.5,0.417
x=0.5 , 0.417

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x3|=|5x2|
without the absolute value bars:

|x|=|y||7x3|=|5x2|
x=+y(7x3)=(5x2)
x=y(7x3)=(5x2)
+x=y(7x3)=(5x2)
x=y(7x3)=(5x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x3|=|5x2|
x=+y , +x=y(7x3)=(5x2)
x=y , x=y(7x3)=(5x2)

2. Solve the two equations for x

9 additional steps

(7x-3)=(5x-2)

Subtract from both sides:

(7x-3)-5x=(5x-2)-5x

Group like terms:

(7x-5x)-3=(5x-2)-5x

Simplify the arithmetic:

2x-3=(5x-2)-5x

Group like terms:

2x-3=(5x-5x)-2

Simplify the arithmetic:

2x3=2

Add to both sides:

(2x-3)+3=-2+3

Simplify the arithmetic:

2x=2+3

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=12

Simplify the fraction:

x=12

10 additional steps

(7x-3)=-(5x-2)

Expand the parentheses:

(7x-3)=-5x+2

Add to both sides:

(7x-3)+5x=(-5x+2)+5x

Group like terms:

(7x+5x)-3=(-5x+2)+5x

Simplify the arithmetic:

12x-3=(-5x+2)+5x

Group like terms:

12x-3=(-5x+5x)+2

Simplify the arithmetic:

12x3=2

Add to both sides:

(12x-3)+3=2+3

Simplify the arithmetic:

12x=2+3

Simplify the arithmetic:

12x=5

Divide both sides by :

(12x)12=512

Simplify the fraction:

x=512

3. List the solutions

x=12,512
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x3|
y=|5x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.