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Solution - Absolute value equations

Exact form: x=52,-25
x=\frac{5}{2} , -\frac{2}{5}
Mixed number form: x=212,-25
x=2\frac{1}{2} , -\frac{2}{5}
Decimal form: x=2.5,0.4
x=2.5 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x3|=|3x+7|
without the absolute value bars:

|x|=|y||7x3|=|3x+7|
x=+y(7x3)=(3x+7)
x=y(7x3)=(3x+7)
+x=y(7x3)=(3x+7)
x=y(7x3)=(3x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x3|=|3x+7|
x=+y , +x=y(7x3)=(3x+7)
x=y , x=y(7x3)=(3x+7)

2. Solve the two equations for x

11 additional steps

(7x-3)=(3x+7)

Subtract from both sides:

(7x-3)-3x=(3x+7)-3x

Group like terms:

(7x-3x)-3=(3x+7)-3x

Simplify the arithmetic:

4x-3=(3x+7)-3x

Group like terms:

4x-3=(3x-3x)+7

Simplify the arithmetic:

4x3=7

Add to both sides:

(4x-3)+3=7+3

Simplify the arithmetic:

4x=7+3

Simplify the arithmetic:

4x=10

Divide both sides by :

(4x)4=104

Simplify the fraction:

x=104

Find the greatest common factor of the numerator and denominator:

x=(5·2)(2·2)

Factor out and cancel the greatest common factor:

x=52

12 additional steps

(7x-3)=-(3x+7)

Expand the parentheses:

(7x-3)=-3x-7

Add to both sides:

(7x-3)+3x=(-3x-7)+3x

Group like terms:

(7x+3x)-3=(-3x-7)+3x

Simplify the arithmetic:

10x-3=(-3x-7)+3x

Group like terms:

10x-3=(-3x+3x)-7

Simplify the arithmetic:

10x3=7

Add to both sides:

(10x-3)+3=-7+3

Simplify the arithmetic:

10x=7+3

Simplify the arithmetic:

10x=4

Divide both sides by :

(10x)10=-410

Simplify the fraction:

x=-410

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(5·2)

Factor out and cancel the greatest common factor:

x=-25

3. List the solutions

x=52,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x3|
y=|3x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.