Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=3,1511
x=3 , \frac{15}{11}
Mixed number form: x=3,1411
x=3 , 1\frac{4}{11}
Decimal form: x=3,1.364
x=3 , 1.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x12|=|4x3|
without the absolute value bars:

|x|=|y||7x12|=|4x3|
x=+y(7x12)=(4x3)
x=y(7x12)=(4x3)
+x=y(7x12)=(4x3)
x=y(7x12)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x12|=|4x3|
x=+y , +x=y(7x12)=(4x3)
x=y , x=y(7x12)=(4x3)

2. Solve the two equations for x

11 additional steps

(7x-12)=(4x-3)

Subtract from both sides:

(7x-12)-4x=(4x-3)-4x

Group like terms:

(7x-4x)-12=(4x-3)-4x

Simplify the arithmetic:

3x-12=(4x-3)-4x

Group like terms:

3x-12=(4x-4x)-3

Simplify the arithmetic:

3x12=3

Add to both sides:

(3x-12)+12=-3+12

Simplify the arithmetic:

3x=3+12

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=93

Simplify the fraction:

x=93

Find the greatest common factor of the numerator and denominator:

x=(3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

10 additional steps

(7x-12)=-(4x-3)

Expand the parentheses:

(7x-12)=-4x+3

Add to both sides:

(7x-12)+4x=(-4x+3)+4x

Group like terms:

(7x+4x)-12=(-4x+3)+4x

Simplify the arithmetic:

11x-12=(-4x+3)+4x

Group like terms:

11x-12=(-4x+4x)+3

Simplify the arithmetic:

11x12=3

Add to both sides:

(11x-12)+12=3+12

Simplify the arithmetic:

11x=3+12

Simplify the arithmetic:

11x=15

Divide both sides by :

(11x)11=1511

Simplify the fraction:

x=1511

3. List the solutions

x=3,1511
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x12|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.