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Solution - Absolute value equations

Exact form: x=6,411
x=6 , \frac{4}{11}
Decimal form: x=6,0.364
x=6 , 0.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x11|=|4x+7|
without the absolute value bars:

|x|=|y||7x11|=|4x+7|
x=+y(7x11)=(4x+7)
x=y(7x11)=(4x+7)
+x=y(7x11)=(4x+7)
x=y(7x11)=(4x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x11|=|4x+7|
x=+y , +x=y(7x11)=(4x+7)
x=y , x=y(7x11)=(4x+7)

2. Solve the two equations for x

11 additional steps

(7x-11)=(4x+7)

Subtract from both sides:

(7x-11)-4x=(4x+7)-4x

Group like terms:

(7x-4x)-11=(4x+7)-4x

Simplify the arithmetic:

3x-11=(4x+7)-4x

Group like terms:

3x-11=(4x-4x)+7

Simplify the arithmetic:

3x11=7

Add to both sides:

(3x-11)+11=7+11

Simplify the arithmetic:

3x=7+11

Simplify the arithmetic:

3x=18

Divide both sides by :

(3x)3=183

Simplify the fraction:

x=183

Find the greatest common factor of the numerator and denominator:

x=(6·3)(1·3)

Factor out and cancel the greatest common factor:

x=6

10 additional steps

(7x-11)=-(4x+7)

Expand the parentheses:

(7x-11)=-4x-7

Add to both sides:

(7x-11)+4x=(-4x-7)+4x

Group like terms:

(7x+4x)-11=(-4x-7)+4x

Simplify the arithmetic:

11x-11=(-4x-7)+4x

Group like terms:

11x-11=(-4x+4x)-7

Simplify the arithmetic:

11x11=7

Add to both sides:

(11x-11)+11=-7+11

Simplify the arithmetic:

11x=7+11

Simplify the arithmetic:

11x=4

Divide both sides by :

(11x)11=411

Simplify the fraction:

x=411

3. List the solutions

x=6,411
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x11|
y=|4x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.