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Solution - Absolute value equations

Exact form: x=53,-1911
x=\frac{5}{3} , -\frac{19}{11}
Mixed number form: x=123,-1811
x=1\frac{2}{3} , -1\frac{8}{11}
Decimal form: x=1.667,1.727
x=1.667 , -1.727

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x+7|=|4x+12|
without the absolute value bars:

|x|=|y||7x+7|=|4x+12|
x=+y(7x+7)=(4x+12)
x=y(7x+7)=(4x+12)
+x=y(7x+7)=(4x+12)
x=y(7x+7)=(4x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x+7|=|4x+12|
x=+y , +x=y(7x+7)=(4x+12)
x=y , x=y(7x+7)=(4x+12)

2. Solve the two equations for x

9 additional steps

(7x+7)=(4x+12)

Subtract from both sides:

(7x+7)-4x=(4x+12)-4x

Group like terms:

(7x-4x)+7=(4x+12)-4x

Simplify the arithmetic:

3x+7=(4x+12)-4x

Group like terms:

3x+7=(4x-4x)+12

Simplify the arithmetic:

3x+7=12

Subtract from both sides:

(3x+7)-7=12-7

Simplify the arithmetic:

3x=127

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=53

Simplify the fraction:

x=53

10 additional steps

(7x+7)=-(4x+12)

Expand the parentheses:

(7x+7)=-4x-12

Add to both sides:

(7x+7)+4x=(-4x-12)+4x

Group like terms:

(7x+4x)+7=(-4x-12)+4x

Simplify the arithmetic:

11x+7=(-4x-12)+4x

Group like terms:

11x+7=(-4x+4x)-12

Simplify the arithmetic:

11x+7=12

Subtract from both sides:

(11x+7)-7=-12-7

Simplify the arithmetic:

11x=127

Simplify the arithmetic:

11x=19

Divide both sides by :

(11x)11=-1911

Simplify the fraction:

x=-1911

3. List the solutions

x=53,-1911
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x+7|
y=|4x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.