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Solution - Absolute value equations

Exact form: x=2,-23
x=2 , -\frac{2}{3}
Decimal form: x=2,0.667
x=2 , -0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x+6|=|8x+4|
without the absolute value bars:

|x|=|y||7x+6|=|8x+4|
x=+y(7x+6)=(8x+4)
x=y(7x+6)=(8x+4)
+x=y(7x+6)=(8x+4)
x=y(7x+6)=(8x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x+6|=|8x+4|
x=+y , +x=y(7x+6)=(8x+4)
x=y , x=y(7x+6)=(8x+4)

2. Solve the two equations for x

10 additional steps

(7x+6)=(8x+4)

Subtract from both sides:

(7x+6)-8x=(8x+4)-8x

Group like terms:

(7x-8x)+6=(8x+4)-8x

Simplify the arithmetic:

-x+6=(8x+4)-8x

Group like terms:

-x+6=(8x-8x)+4

Simplify the arithmetic:

x+6=4

Subtract from both sides:

(-x+6)-6=4-6

Simplify the arithmetic:

x=46

Simplify the arithmetic:

x=2

Multiply both sides by :

-x·-1=-2·-1

Remove the one(s):

x=-2·-1

Simplify the arithmetic:

x=2

12 additional steps

(7x+6)=-(8x+4)

Expand the parentheses:

(7x+6)=-8x-4

Add to both sides:

(7x+6)+8x=(-8x-4)+8x

Group like terms:

(7x+8x)+6=(-8x-4)+8x

Simplify the arithmetic:

15x+6=(-8x-4)+8x

Group like terms:

15x+6=(-8x+8x)-4

Simplify the arithmetic:

15x+6=4

Subtract from both sides:

(15x+6)-6=-4-6

Simplify the arithmetic:

15x=46

Simplify the arithmetic:

15x=10

Divide both sides by :

(15x)15=-1015

Simplify the fraction:

x=-1015

Find the greatest common factor of the numerator and denominator:

x=(-2·5)(3·5)

Factor out and cancel the greatest common factor:

x=-23

3. List the solutions

x=2,-23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x+6|
y=|8x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.